Optimal. Leaf size=150 \[ \frac {2 \left (a+b \tanh ^{-1}(c x)\right )}{c^3 d^3 (c x+1)}-\frac {a+b \tanh ^{-1}(c x)}{2 c^3 d^3 (c x+1)^2}-\frac {\log \left (\frac {2}{c x+1}\right ) \left (a+b \tanh ^{-1}(c x)\right )}{c^3 d^3}+\frac {b \text {Li}_2\left (1-\frac {2}{c x+1}\right )}{2 c^3 d^3}+\frac {7 b}{8 c^3 d^3 (c x+1)}-\frac {b}{8 c^3 d^3 (c x+1)^2}-\frac {7 b \tanh ^{-1}(c x)}{8 c^3 d^3} \]
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Rubi [A] time = 0.22, antiderivative size = 150, normalized size of antiderivative = 1.00, number of steps used = 15, number of rules used = 8, integrand size = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.400, Rules used = {5940, 5926, 627, 44, 207, 5918, 2402, 2315} \[ \frac {b \text {PolyLog}\left (2,1-\frac {2}{c x+1}\right )}{2 c^3 d^3}+\frac {2 \left (a+b \tanh ^{-1}(c x)\right )}{c^3 d^3 (c x+1)}-\frac {a+b \tanh ^{-1}(c x)}{2 c^3 d^3 (c x+1)^2}-\frac {\log \left (\frac {2}{c x+1}\right ) \left (a+b \tanh ^{-1}(c x)\right )}{c^3 d^3}+\frac {7 b}{8 c^3 d^3 (c x+1)}-\frac {b}{8 c^3 d^3 (c x+1)^2}-\frac {7 b \tanh ^{-1}(c x)}{8 c^3 d^3} \]
Antiderivative was successfully verified.
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Rule 44
Rule 207
Rule 627
Rule 2315
Rule 2402
Rule 5918
Rule 5926
Rule 5940
Rubi steps
\begin {align*} \int \frac {x^2 \left (a+b \tanh ^{-1}(c x)\right )}{(d+c d x)^3} \, dx &=\int \left (\frac {a+b \tanh ^{-1}(c x)}{c^2 d^3 (1+c x)^3}-\frac {2 \left (a+b \tanh ^{-1}(c x)\right )}{c^2 d^3 (1+c x)^2}+\frac {a+b \tanh ^{-1}(c x)}{c^2 d^3 (1+c x)}\right ) \, dx\\ &=\frac {\int \frac {a+b \tanh ^{-1}(c x)}{(1+c x)^3} \, dx}{c^2 d^3}+\frac {\int \frac {a+b \tanh ^{-1}(c x)}{1+c x} \, dx}{c^2 d^3}-\frac {2 \int \frac {a+b \tanh ^{-1}(c x)}{(1+c x)^2} \, dx}{c^2 d^3}\\ &=-\frac {a+b \tanh ^{-1}(c x)}{2 c^3 d^3 (1+c x)^2}+\frac {2 \left (a+b \tanh ^{-1}(c x)\right )}{c^3 d^3 (1+c x)}-\frac {\left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac {2}{1+c x}\right )}{c^3 d^3}+\frac {b \int \frac {1}{(1+c x)^2 \left (1-c^2 x^2\right )} \, dx}{2 c^2 d^3}+\frac {b \int \frac {\log \left (\frac {2}{1+c x}\right )}{1-c^2 x^2} \, dx}{c^2 d^3}-\frac {(2 b) \int \frac {1}{(1+c x) \left (1-c^2 x^2\right )} \, dx}{c^2 d^3}\\ &=-\frac {a+b \tanh ^{-1}(c x)}{2 c^3 d^3 (1+c x)^2}+\frac {2 \left (a+b \tanh ^{-1}(c x)\right )}{c^3 d^3 (1+c x)}-\frac {\left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac {2}{1+c x}\right )}{c^3 d^3}+\frac {b \operatorname {Subst}\left (\int \frac {\log (2 x)}{1-2 x} \, dx,x,\frac {1}{1+c x}\right )}{c^3 d^3}+\frac {b \int \frac {1}{(1-c x) (1+c x)^3} \, dx}{2 c^2 d^3}-\frac {(2 b) \int \frac {1}{(1-c x) (1+c x)^2} \, dx}{c^2 d^3}\\ &=-\frac {a+b \tanh ^{-1}(c x)}{2 c^3 d^3 (1+c x)^2}+\frac {2 \left (a+b \tanh ^{-1}(c x)\right )}{c^3 d^3 (1+c x)}-\frac {\left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac {2}{1+c x}\right )}{c^3 d^3}+\frac {b \text {Li}_2\left (1-\frac {2}{1+c x}\right )}{2 c^3 d^3}+\frac {b \int \left (\frac {1}{2 (1+c x)^3}+\frac {1}{4 (1+c x)^2}-\frac {1}{4 \left (-1+c^2 x^2\right )}\right ) \, dx}{2 c^2 d^3}-\frac {(2 b) \int \left (\frac {1}{2 (1+c x)^2}-\frac {1}{2 \left (-1+c^2 x^2\right )}\right ) \, dx}{c^2 d^3}\\ &=-\frac {b}{8 c^3 d^3 (1+c x)^2}+\frac {7 b}{8 c^3 d^3 (1+c x)}-\frac {a+b \tanh ^{-1}(c x)}{2 c^3 d^3 (1+c x)^2}+\frac {2 \left (a+b \tanh ^{-1}(c x)\right )}{c^3 d^3 (1+c x)}-\frac {\left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac {2}{1+c x}\right )}{c^3 d^3}+\frac {b \text {Li}_2\left (1-\frac {2}{1+c x}\right )}{2 c^3 d^3}-\frac {b \int \frac {1}{-1+c^2 x^2} \, dx}{8 c^2 d^3}+\frac {b \int \frac {1}{-1+c^2 x^2} \, dx}{c^2 d^3}\\ &=-\frac {b}{8 c^3 d^3 (1+c x)^2}+\frac {7 b}{8 c^3 d^3 (1+c x)}-\frac {7 b \tanh ^{-1}(c x)}{8 c^3 d^3}-\frac {a+b \tanh ^{-1}(c x)}{2 c^3 d^3 (1+c x)^2}+\frac {2 \left (a+b \tanh ^{-1}(c x)\right )}{c^3 d^3 (1+c x)}-\frac {\left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac {2}{1+c x}\right )}{c^3 d^3}+\frac {b \text {Li}_2\left (1-\frac {2}{1+c x}\right )}{2 c^3 d^3}\\ \end {align*}
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Mathematica [A] time = 0.49, size = 145, normalized size = 0.97 \[ \frac {\frac {64 a}{c x+1}-\frac {16 a}{(c x+1)^2}+32 a \log (c x+1)+b \left (16 \text {Li}_2\left (-e^{-2 \tanh ^{-1}(c x)}\right )-12 \sinh \left (2 \tanh ^{-1}(c x)\right )+\sinh \left (4 \tanh ^{-1}(c x)\right )+12 \cosh \left (2 \tanh ^{-1}(c x)\right )-\cosh \left (4 \tanh ^{-1}(c x)\right )+4 \tanh ^{-1}(c x) \left (-8 \log \left (e^{-2 \tanh ^{-1}(c x)}+1\right )-6 \sinh \left (2 \tanh ^{-1}(c x)\right )+\sinh \left (4 \tanh ^{-1}(c x)\right )+6 \cosh \left (2 \tanh ^{-1}(c x)\right )-\cosh \left (4 \tanh ^{-1}(c x)\right )\right )\right )}{32 c^3 d^3} \]
Warning: Unable to verify antiderivative.
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fricas [F] time = 0.56, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {b x^{2} \operatorname {artanh}\left (c x\right ) + a x^{2}}{c^{3} d^{3} x^{3} + 3 \, c^{2} d^{3} x^{2} + 3 \, c d^{3} x + d^{3}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (b \operatorname {artanh}\left (c x\right ) + a\right )} x^{2}}{{\left (c d x + d\right )}^{3}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.06, size = 246, normalized size = 1.64 \[ -\frac {a}{2 c^{3} d^{3} \left (c x +1\right )^{2}}+\frac {2 a}{c^{3} d^{3} \left (c x +1\right )}+\frac {a \ln \left (c x +1\right )}{c^{3} d^{3}}-\frac {b \arctanh \left (c x \right )}{2 c^{3} d^{3} \left (c x +1\right )^{2}}+\frac {2 b \arctanh \left (c x \right )}{c^{3} d^{3} \left (c x +1\right )}+\frac {b \arctanh \left (c x \right ) \ln \left (c x +1\right )}{c^{3} d^{3}}-\frac {b \ln \left (c x +1\right )^{2}}{4 c^{3} d^{3}}+\frac {b \ln \left (-\frac {c x}{2}+\frac {1}{2}\right ) \ln \left (c x +1\right )}{2 c^{3} d^{3}}-\frac {b \ln \left (-\frac {c x}{2}+\frac {1}{2}\right ) \ln \left (\frac {1}{2}+\frac {c x}{2}\right )}{2 c^{3} d^{3}}-\frac {b \dilog \left (\frac {1}{2}+\frac {c x}{2}\right )}{2 c^{3} d^{3}}-\frac {b}{8 c^{3} d^{3} \left (c x +1\right )^{2}}+\frac {7 b}{8 c^{3} d^{3} \left (c x +1\right )}-\frac {7 b \ln \left (c x +1\right )}{16 c^{3} d^{3}}+\frac {7 b \ln \left (c x -1\right )}{16 c^{3} d^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \frac {1}{32} \, {\left (64 \, c^{3} \int \frac {x^{3} \log \left (c x + 1\right )}{2 \, {\left (c^{6} d^{3} x^{4} + 2 \, c^{5} d^{3} x^{3} - 2 \, c^{3} d^{3} x - c^{2} d^{3}\right )}}\,{d x} - 4 \, c^{2} {\left (\frac {2 \, {\left (3 \, c x + 2\right )}}{c^{7} d^{3} x^{2} + 2 \, c^{6} d^{3} x + c^{5} d^{3}} + \frac {\log \left (c x + 1\right )}{c^{5} d^{3}} - \frac {\log \left (c x - 1\right )}{c^{5} d^{3}}\right )} + 64 \, c^{2} \int \frac {x^{2} \log \left (c x + 1\right )}{2 \, {\left (c^{6} d^{3} x^{4} + 2 \, c^{5} d^{3} x^{3} - 2 \, c^{3} d^{3} x - c^{2} d^{3}\right )}}\,{d x} + 7 \, c {\left (\frac {2 \, x}{c^{5} d^{3} x^{2} + 2 \, c^{4} d^{3} x + c^{3} d^{3}} - \frac {\log \left (c x + 1\right )}{c^{4} d^{3}} + \frac {\log \left (c x - 1\right )}{c^{4} d^{3}}\right )} + 96 \, c \int \frac {x \log \left (c x + 1\right )}{2 \, {\left (c^{6} d^{3} x^{4} + 2 \, c^{5} d^{3} x^{3} - 2 \, c^{3} d^{3} x - c^{2} d^{3}\right )}}\,{d x} - \frac {8 \, {\left (4 \, c x + 2 \, {\left (c^{2} x^{2} + 2 \, c x + 1\right )} \log \left (c x + 1\right ) + 3\right )} \log \left (-c x + 1\right )}{c^{5} d^{3} x^{2} + 2 \, c^{4} d^{3} x + c^{3} d^{3}} + \frac {6 \, {\left (c x + 2\right )}}{c^{5} d^{3} x^{2} + 2 \, c^{4} d^{3} x + c^{3} d^{3}} - \frac {3 \, \log \left (c x + 1\right )}{c^{3} d^{3}} + \frac {3 \, \log \left (c x - 1\right )}{c^{3} d^{3}} + 32 \, \int \frac {\log \left (c x + 1\right )}{2 \, {\left (c^{6} d^{3} x^{4} + 2 \, c^{5} d^{3} x^{3} - 2 \, c^{3} d^{3} x - c^{2} d^{3}\right )}}\,{d x}\right )} b + \frac {1}{2} \, a {\left (\frac {4 \, c x + 3}{c^{5} d^{3} x^{2} + 2 \, c^{4} d^{3} x + c^{3} d^{3}} + \frac {2 \, \log \left (c x + 1\right )}{c^{3} d^{3}}\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {x^2\,\left (a+b\,\mathrm {atanh}\left (c\,x\right )\right )}{{\left (d+c\,d\,x\right )}^3} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \frac {\int \frac {a x^{2}}{c^{3} x^{3} + 3 c^{2} x^{2} + 3 c x + 1}\, dx + \int \frac {b x^{2} \operatorname {atanh}{\left (c x \right )}}{c^{3} x^{3} + 3 c^{2} x^{2} + 3 c x + 1}\, dx}{d^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
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